1.
$<E. 3 3 D<<5D ?D< ?D>E?GL<64=<<
1. =>?>4 ?DO<>7> 4>EFG?4, ?564O: G<5=LL5=<5 7D><>>EF<
2. =>?>4 ?DO<>7> 4>EFG?4, ?D464O: ?>6OL5=<5 7D><>>EF<
3. =>?>4 ?DO<>7> 4>EFG?4, ED54=OO: 557 76G>4
2. &5E=<G5E><5 E4D4>F5D<EF<><
5>7=4G5=<5
<4?47>= G4EF>F
$45>G4O F5<?5D4FGD4
D><76>4<F5?L=>EFL
<E??5=
'D>65=L 7D><>>EF<
%<<6>?
4>E<<4?L=O= GD>65=L =4?DO65=<O =4 6OE>45 4?O
?>4>?NG5=<O D57<EFD<DGNM57> GEFD>=EF64
4GL=<>< E 74M<F>= >F 6=5L=<E <EF>G=<>>6 LG<4
6F><4F<G5E>>5 >F>?NG5=<5
>>G<G?OF>D=4O 54F4D5O
D5<O D45>FO >F 54F4D5<
?<=4 7>=44
5E
- 5M<= 65E
- D<5>D
- 4GL=<><
$47<5DO ?D<5>D4
$47<5DO >5=E4
48 RU
2.
3.
1.
$<E. 4 3 D<<5D 557 76G>4
TKST 11
30 F - 15 >F
>F -10 4> +45 °C (14-113 °F)
$57G?<D>6>4 E 15 GD>6=O<<
>=>ED><=O= -4<E??5=
65DE < 6=<7
4F4D5O E44<FEO
250 <
32 < (?D46O= < ?56O= 6<5EF5)
4, G5D57 10 <<=
2 × M5?>G=O5 54F4D5< F<?4
(6E>4OF 6 >><??5>F ?>EF46><)
<<=. 30 G4E>6 =5?D5DO6=>= D45>FO
70 < 300 << (2.8 < 11.8 4N=<4)
1670 7 (3.68 DG=F4)
290 7 (0.64 DG=F4)
290 7 (0.64 DG=F4)
230 × 70 × 38 << (9 × 2.8 × 1.5 4N=<4)
360 × 110 × 260 << (14.2 × 4,. × 10.2 4N=<4)
2.
3.